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Band I.
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Beispiel 1.

149

15 N

[ S p 4

löö ■ “2 ' " y

y 100 i

-T-]

-22.5

5000 0.5 1.03 — 1

100 ' 2 ’ y — 1= 12.5 X 31.5= 393.75

N

= r

Lioo

p

y 10 - 1 1y — 1 J

-15

_ 5000 1.03 — 1

~ 100 ’ U ’ 5 ' 1.03 — 11.558 — 1= 20 51)3

= 25 X 18.6

= 465

’=E

SN

„10

i_ iP4

100 ' 3 ' y — 1

- 45

5000 4 X 0.5 1.03 — 1

100 • 3 ' 1.03 — 1

100 3.7826 — 1“3" ~T03 — 1

ioo x

92.75

3

= 3091.667

_ r — z 1*4

_ LlOO ■ 4

y -3r]

_

5000 7 X 0.5 1.03 -

TÖÖ '

50 .

4 ' 1.03

3.5 2.428 — 1

1.03

1

= ? X 47.6

= 175 X H.9- 2082.5

N

- 135

1.03 =

54.125

N

- 112.5

1.03 =

27.829

N

-90

1.03 =

14.308

N

- 75

1.03 =

9.183