Beispiel 1.

151

n

- 5

2000 „ 1.03 - 1

- 1Ö0 ' 1,0 ' 1.03 - 1

= 30

1.159 — 1

0 03= 33 X 5.3= 174.9

-[

s

.100

3n

10

2000

TW

i P-i y_

3 y -

4 x 1.5

= 40 ——0.03

= 40 X 18-6= 744.00

fl

-15

1.03 — 11.03 — 1

r fl

Lioo

2000

100

7 Pj4

flfl

7 X 1.5

— io1.03 — 1

4 • 1.03

1.344 —_1070352.5 X 11-467602.018

= 5 X 10-5

y- n -45

y 10 = 1.03 = 3.7826

fl n -37.5

y 4 = 1.03 = 3.0304

fl n -30

y 5 = 1.03 = 2.428

fl n -25

y 2 = 1.03 = 2.094

fl n -10

y 5 = 103 = 1.344

W 18 = 124.619 [(39.75 X 3.7826) + (82.66 X 3.0304) + (123.99 X 2.428) +

+ (174.9 X2.094) + (744.00X 1-344)+ 602.0isj|

= 24.619 | 150.357l 250.493] 301.048j 366.241/ 999.936' 602.018

W 18 = 24.619 X 2670.093W 18 = 65735.020