E The Eeneral Oſe M the caumi PRO pP. VI.

Having ino Sides a rigbt- lined Trlangle, and be Aygle betmeenbbſem, to find the Content.

A ad che sine of che Angle, and the Logarithms of boch che Sicles,A from che Sum of cheſe fubtract 10.3010 300, ſo the Remainderhall be the Logarichm of the Content.

— As in che Triangle A DB, having the Sides A B 335, A D 100,and che Angle B A D 43 g. 20 fn.

The Sine of che Angle 43 gr. 20 mn. is 9.836477The Logarithm of che Side AB 335 2.550448The Logarithm of che Side AD 100 2. oοοοThe Sum of cheſe make f a 14.3615218From which ſubtract the ſolemn Logarichm 10. 301930

The Remainder will beThe Logarichm of 1 1494 che Content required.

PRO P. VII.

Having tbree Auglis, and one Hide HF 4 right. lined Triangle, 10 findthe Content. a72 the double of the Logarithm of the Side given, and the Sines of. che two next Angles: from the Sum of theſe ſubtract che Sum of10.010300, and the Sine of the oppoſite Angle, ſo the Remainderhall be the Logarithm of the Content. 3As in the Triangle ADB ſuppofing the Angles B A C to be 34 gr. 20.

BDA 122 gr. o m. ABD 14g. 40. and the Side A Dto the 100 parts.

The Logarithm of the Side AK C 100 15 2. OoοοοοThe ſame again 2. ooOοοο

The sine of the Angle BAS 43 gr. 20 M. 9.8364770The Sine of the Angle B DA 58 o

9 9284204The Sum of theſe four make 23.7648 974Again, if we add the ſolemn Logarithm 10. 301030

To che Sine of the oppoſite Angle 14 gr. 40 1. 9.403474

The Sum of both will make 159.7044854Which ſubtracted from 23.764894 leave 4. 0604120

e The Logarithm of 11492 the Content required.

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