digested intofeveral Propositions. i 9

the Ruler , which will also immediately shew you upon theArk the Suns place to be ^ n or-N. 19. And if the lamedeclination had been Southerly, then mult you have countedit on the limb from N towards E, and the Ruler therelaid Ihewes upon the Ark the degrees of the Ecliptick an-swerable, to be " 1 11, 85 1 p , if then according to the firstProposition, you look the parallels of those degrees in thatInstrument, they (hall be the parallels of the fore-nameddeclinations.

V I. T be intersection of any hour circle with any parallelbeing assignees to snd what altitude the same shall haveabove the Horizon.

T His is useful for many purposes , (as hereafter is(hewed) and most easie to be performed*, For ha-ving your parallel given, you by the last Proposition,i shall fee quickly where every hour circle cuts throughthe lame , unto those intersections apply your Ruler , soshall the degrees of the fame Ruler, being counted from theHorizon, ihew you the Altitudes required: So in » 1, or29, when the day at London is 14. hours long, the Sunsaltitude at 9 or 3 a clock will be 3 6 dcg. above the Horizon:And in <a 19 degrees, the Suns altitude at 9 and 3 a clock,

'vill be 38 degrees; and so of all other parallels andhoures.

^ I I. The dcscendent point of the Ecliptics being assignees tosnd , 1 what point of the Ecliptuh^is in any hour circle, and2 what altitude it hath.

Examp^ V Et the beginning of Leo descend at London ,1JL-would then know what degree of the Ecliptickin the hour of 3 , and in the hour of 10 , at that very in-*Hnt:First,I lay the Ruler upon the beginning of ^ counted in; ark,where I shall find it to cut upon the chord 7 hours,and

9 degrees, which hours are to be taken for afternoon hours:Now from 3 a clock to 7, and 9 degrees afternoon , are 4j°urs, and A degrees, which turned into degrees, makes 69Agrees : And so from 10 a clock, to 7 and 9 degrees after-; | ll °on , are 9 hours , and 9 degrees, or 144 degrees: Thesej __ C 2 being

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