Cii)

PROBLEMA. III.

Latus Biquadraticum c numero (1741583974) Educere?

TEquatio aaaa — f

Numeris aaaa = 2741583974.

theor . x = /— gggg4ggg

f g===5 '~

't — gggg — 11

4ggg — 32) no

1=27(+03—X

20

+ o?

Z = 24 5=274158

f ~ gggg — — 56834ggg — 48668) — 56830 (—001 =x

230

— oox

g —2.29 2.74x583974

~ f—gggg — — 847457

' 4 ggg == 48 035956)—847457-0 (—.1 76 = x

229.

—I .176

g = 228.824

5— gggg — — 29920.256286965764ggg — 47925285.7) — 29920.25628696576 (—,00062439801 =x

228.824

— .00062439^02a = 228.82337560198

B

1

B

PRO