tl
I8S 111. Aufgabe.
cotC ---- 11.04514.36
cotABC = 8- 8391104ABC = 86° 3
~ Cß — 50°
cosCB= 9.8080675cor C =11.0451436
cot ABC = 8-7629239ABC = 86" 41'
cF= 60"
cos CB = 9.6989700cotC =11.0451436
cor ABC = 8-6538264ABC = 87° 25'
CB = 7 o°
cos CB = 9.5340517cotC = 11.0455436
cor ABC = 8-4889081ABC = 88° 14'
CB = 8o°
cos CB — 9.2396702corC =11.0451436
cor ABC = 8- »945266ABC = 89°6'
CB =90'cos CB = o.cot C = 11.
cot ABC = o.
ABC = 90°
ABD = ABC — DBC
DBC =
23°
29'
ABC =
84°
5i'
DBC =
29
29
ABD =
61
22
ABC =
84 56
DBC =
2.3
29
ABD =
61
27
ABC =
85
10
DBC =
23
29
ABD =
61
41
ABC =
85
32
DBC =
23
29
ABD =
62
3
ABC =
86
3
DBC =
23
29
ABD =
62
34
ABC =
86
41
DBC =
23
29
ABD =
63
12
ABC =
87 25
DBC =
23
29
ABD =
63
56
ABC =
88
14
DBC —
23
29
ABD =
64 4Z
ABG