282.

da _

clA! ~

CHAPITRE X.tang A" sinC' = tang G'; ~~ =

cos 2 C' sin C" sin C" __ sin A" sin C __

cos “A 7 ' sin 2 A" sin 2 A" sin A" ~

cos C' cos G sin C" cos G sin C* cos G sin G

24 ?

dC

: cos 2 G 7sin C

c °s C' cosC' sin C*cos a.' cos A'sin2C'

283 ._ JA'_

dA'~

284.

dC_

~ dA'‘

‘ sin A" cos C'cos A' cos A'sin A" cos A'sin A' sinaA'

cosC* sinA' = cos A"; JA' cos A' cos C* = ■— JA" sin A'

cosAco S C" S inA"cosC'cosC" =cosC , cosG , cosC=cotA ^ otA ^

sin A"

sin A"

sin A" sin C = sinC" ; JA" cos A" sin C -f- dC cos C sin A" = o= sin a" ^ c ° t A" tang C—cos C tang A' tang C=sin C tang A'.

285. sinC' tang A" = tangC*; JC' cosC' tang A' - 4 - ~ ^ o s f^~ ^ 0

- dc 'dA"'

286.dedG’

sin G

__ tang C '_a tang G cos A" tangC tangC ,

"cos 2 A''tang A"cos C'" - sin A" cos A"’ Tin 2 A" ‘ sin A" cos A"' Tin A" *

cosC' cosC" c= cosC; — JC' sinC' cosC* = —JC sinC

sinC'cosC" sinA'sinC cosC" . in ^

=—r-^—ss:- r—p, -= sm A cosC =cosA =tangC cotC.

sm C sin C 53

Constantes A! et A* en supposant A' = qo°.

287. Le triangle rectangle en. A' donne d’abord j

,a„gC = cosA' t a n gC' ; ^ = "4?^

dC cos A" cos 2 C tang C cot C' cos 1 C sin C cos C __ sin 2C cos A" cos* C

dC' cos 2 C' cos 2 G' ' sinC'cosC' sinâC? ’ cos 2 C cos ? G*

_ cos A" _cosC" sinA__ sin A

cos 2 C"

cos 2 C" cos C"‘

288. cosC' tang A = COt A'; — JC' sin C' tang A H- — o ;

JC' sinC' sin A cos A = JA cos G' ;

dG _ cotC' _acotC' _ cosC'

dA sinA cos A ' sin2A sinC cosA*

289. sin A* cos C = cos A j — JC sinC sin A' — — JA sin A

de EÛT - = i in c— = SinC = tan S C cot A *= côt(ï‘

1.

32