21

;■ - Astronomy .

Noty r .

the Perihelion i

is in — ,17 12 55 , if we

hcle j 11 7 ” 33" 30", we have the Heliocentric Longi

C 5 ' Al

AT Z 9 ' ? 5 '

f s>

10 the Descending Node - is in tr, 15° 45' ao"

now found, theis the Distance of the Comet

K 41 * wC-** u Ule JJi Jc endin g Mode. is in tt, 15Viiffst 11 c h subtract the Comet’s Place

nr 05 ' 55

^‘^ Node .

f N’tK x C T the perihelion P i s 151 0 27 35 aurantfrt '- t , e ^°de st, it will be but 28° 38'.25" distant

Let the Line of the Nodes be

35

Hv

we deduct PS e? 28° 38' 25"av * ° 58'5"

B S st ;" distant

l ^ e Node V. If then from the Angle Q_S A

. - _ j. - ^ - A S st, we

,26. p ^ st - 3 o ( ^ „.

v>He Q let fall the Perpendicular Q_N on the

*

the 5“ 4 , 90° = 10.00000a

^ is the the An S Ie Q? N “ 33’ 58' — 9-747374

y 5lde SQ = 0,82650 = 9.917227

. ——-

, en gth bf the Side QNz=o;462oO == 9.664601

V 7 - A :

then in the Right-angled Triangleih\ ^ v ’ n § the Angle at S and the Side S Q_, weK ad Q . Q.N as follows.

j 6 : the Right-angled Triangle Q_N D

* Side now found Q-N, and the Angle of the

vy tion r>f -e. _r-i-u;.. nun — x-° ^

1 the the ComePs Orbit, Q.N D — 47° y', toI lUd' e or perpendicular Q_D. Thus fay,

-90° =-10.000000°*s th R ' p ne °fInclination QND—47 J 9' — 9.805138v S ‘de QN = 0,46200= 9.664601

Q th e b . - -

j. 38 . t v rpend!cular Q.D = 0,33860- 9.529739

A Coil Ve Can now find the Heliocentric Latitude ofr the ot the Angle Q_S D ; fors W_. (le Q_S =0,82650= 9.917227

QT> = 0,33860 = 9.529739

hh e

H ;

7 ,

a di Us

0 0 .

Ol

90 J

10.000000

' ne t

j \ -p 0f Helioc. Lat. Q_SD = 24° 12'= 9.6x25121111 the Comet’s Curtate Distance from the

PlateLXILF lg: 2

7 ' 15 , we have this Analogy from the Right-

sl ^gk Q_ S D.

P % M,