ASTRONOMY.

10 #

As Radius qo°~ t°- C f 0 op

To the Sine of the Angle S Q_D ~ 65° 48 — 9'9 - 3 z 7So is the Side S Qj= 0,82650 3: 9 , 9 ^^‘

To the Curtate Distance 8 D — 0,75380 — 9 '^qyi'30. To find the Side N D in the Right-angl e

0#

angle QND, fay,

As Radius 9 o°"~

To Co-sine of Inclination DQN=42° 5T= 9 '^.^So is the Side Q_N n 0,4620 o —

To the Side DNr 0,31420 = 9 '^

31. Then in the Right-angled Triangles gjjji'can find the Heliocentric Place of the Comet in t" etic, or Angle D S N, thus: anl^l

As the Curtate Distance 8 D — 0,75380 —

To the Side ND = 0,31420= ^'^0°°°

ro.o°°i

To the Side

So is Radius 90->

To the Sine of the Angle DSN = 24° 38'=Therefore to the Place of the Node SI, 8 *6 c°

Add the Angle now found 24 0 ^

93

4 >

TheSumistheHelioc.PlaceintheEclrptic, n l° £sl f

32. The next thing to be done is to find the ^Qfb lCthe Sun, and consequently of the Earth in Wfor the given Time; which is calculated from th ein the usual Method as follows:

1741.„ 3 -

fan. 23.Hours 6Min. 11

Mot. of the Sun.S. v

9 21 1 .58

11 29 17 0000 22 40 1214 4727

Mot. of Perihelion .S ' « ' ,f

- 3 8 13 3 °

? 3 °3

MeanMot.io 13 14 24 -Equat.add. 1 7 39

True Place 10 14 22 3

- 3 8 16 310 13 14 24

458 21