300 Description and Use of the

at the same time, that the nut at the up-per end of it may be exactly in the zenith,where six it, and the triangle P Z G willbe formed.

The arch P Z, of the strong brass meri-dian, contains 56° 40', the quantity of therequired side C D, and the arch P G 114 030', is equal to the other required side B D,the angle DBG may be found by art. 332,or 339.

CASE III.

PROBLEM LXXIII.

Two sides and their contained anglegiven, to find the rest.

In the oblique angled triangle BCD,sig. 32. are given

0 ' <

r gQ g~ IJ 1

the fides j ^ I to find j

the angle BCD 125 30) L

the side B Dthe angles £•

341. Fig. 30. Count the side CD 56°40' from P to Z on the strong brass me-ridian ; bring the point Z into the zenith,and to it fix the quadrant of altitude, and

number