MEN
196
MEN
divide it into several lengths, and find the content of eachpart separately.
“ 2. This rule, which is commonly used, gives the answerabout one-fourth less than the true quantity in the tree, ornearly what the quantity would be after the tree is hewedsquare in the usual way ; so that it seems intended to makean allowance for the squaring of the tree. When the truequantity is desired, use the second rule given below.
“Example 1.—A piece of round timber being 9 feet 6inches long, and its mean quarter-girt 42 inches ; what isthe content ?
Decimals. Duodecimals.
3.5
quarter girt
3 6
3.5
3 6
175
10 6
105
1 9
12.25
12 3
9.5
length
9 6
6125
110 3
11025
6 1
116.375
content
116 4
it
By the sliding rule.
0
D D
c
As 9.5
: 10 : s 35
: lie*
Or 9.5
: 12 : : 42
: nei
“ Example 2.—The length of a tree is 24 feet, its girt atthe thicker end 14 feet, and at the smaller end 2 feet;required the content.—Answer 96 feet.
“ Example 3.—What is the content of a tree, whose meangirt is 3.15 feet, and length 14 feet 6 inches ?—Answer,8.9922 feet.
“ Example 4.—Required the content of a tree, whoselength is 17£ feet, and which girts in five different places asfollows, namely, in the first place 9.43 feet, in the second7.92, in the third 6.15, in the fourth 4.74, and in the fifth3.16.—Answer, 42,5195.
“ Rule 2.—Multiply the square of one-fifth of the meangirt by double the length, and the product will be the con-tent, very near the truth.
“ Bp the sliding Rule .—As the double length on C : 12 0
on t> :: £ of the girt, in 12ths or lOths, on d : content o“ Example 1.—What is the content of a tree, its l eI1 ®being 9 feet 6 inches, and its mean girt 14 feet ?
Decimals.
Duodecimals.
2.8
J- of girt
2
9
7
2.8
2
9
7
224
5
7
2
56
2
1
3
7.84
1
8
19
—
7
10
1
7056
784
19
148.96
content
148
11
7
((
By the sliding rule.
c
D
D
C
As
19
: 10 : :
28 : 149.
Or
19
: 12 : ;
33 t <V : 149.
"" - - - - - 1 u . , jj i-
“ Example 2. —Required the content of a tree, whicfeet long, and mean girt 8 feet.—Answer, 122.88 feet' ^
“ Example 3.—The length of a tree is 14^ feet, an ^ ;
girt 3.15 feet; what is the content ?—Answer, ll.ol ^ jy |“ Example 4. —The length of a tree is 17^ f eet ’ i
mean girt 6.28 ; what is the content ?—Answer, 54.40o° j C |i“ Note 1.—That part of a tree, or of the branches, ^gjrt, jis less than 2 feet in circumference, or 6 inches quart |
is cutoff; not being accounted timber. , Mt * * 6 * 8 '
“ 2.—Fifty cubic feet of timber make a load ; andfore, to reduce feet to loads, divide them by 50.” „ ^t-
Example. —How many loads of timber are there in « i
5,0 ) 24,8 I
4 48
So that this quantity contains four loads and 48 ft et '
It is customary, however, to make a difference tO°tsquare and round timber, in many places. The load r°e. tilfitftimber containing 50 cubic feet, while that of jjH'
contains only 40. This allowance is reasonable, onof the waste.
“ A Table,
“ For readily finding the Content of Trees, according to the common Method of measuring Timber.
“ Rule. —Seek the quarter-girt in the first column towards the left-hand, and take out the number opposite,that number by the length of the tree in feet, &c. and the product will be the content in solid feet,
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