178 GEODÆSIA Improved.

Example III,

Admit fig. 3, plate 2, to represent an Inclosure the Properlyof three Men, (viz, Joseph , John and James.) containing 21Ac et, 3 Roods, 12 Perches, to be divided equally, that is tofay, eacn to have 7 Acres, 1 Rood, and 4 Fetches; and theLines of Division to terminate at, and communicate with a Pondof Wa.er that is therein, so that each Person may have the Be-nefit thereof, and n^t trespass upon one another’s Land.

A. R. p. P.

Joseph — 7 z 4 = 1164

John — 7 1 4 = 1164

James — 7 I 4 = 1164

21 3 12 = 3492

To effect this (after having fixt upon the Situation of eachPart, t>y fixing Marls at A and E,) first straighten theHedge A F E, by taking up the Off-set (as hath been taught inthe fi r st Example of the preceding Chapter) ALEE; and, inchaining the Base thereof, measure the Perpeneicular Lo: Hav-ing smithed this Part, cast up the Dimensions thereof in thethe Field, which amount to 1110 square Perches, being too littleby 54, seeing each Man's Proportion is 1164 square Perches,as above.

Secondly, Meastire the Trapezium A B 0, and you’ll findthat it domains 1126 square Perches, being too little also by38 Now, as you know the Field to contain just 3492 squareFetches. , ou need only take 38 from the Part unmeasured, viz.G C D E o, and adjoin it to the last measured Part, namely,the Trapezium A B G O ; and also take 54 square Perches fromthe other Side of the unmeasured Share or Part, and lay it to thefirst measured Part, then is the F Id divided a* required. How-ever, to prove the Work, it will not be amiss to measure thethud and last Part, as you did the two former, (ere youtake any thing therefrom.) and finding it to be 1256 squarePerches, that is, 92 too much ; nevertheless, collect those dif-fering Shares together, viz. no -j- 1x26 -f- 1256 = 3492,

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