350 APPENDIX.
which you arc to multiply, the mean area to find the solidity.
Example 2. Let fig. 9, plate 5, represent a large hay reek, thelength whereof is 20 yards, and the other dimensions as under-neath, how many (olid yards are contained therein?Dimensions.
Bottom part of eafi end. yds.Breadth C L at bulge 5.1 c? _Breadth P q at bottom 4.60 5Height M N 1 qo
Top part of eaji end.
Breadth at bulge
5 - 10
5 -°
Breadths, each a yard
4.90
higher than the other
3 30
2.60
Breadth at the top
1.30
6)
22 20
Mean breadth
3-7
Height N O
LL
Bottom part oj voejt end.
Breadth at bulge 4.60
Breadth at bottom 4.0
Height 1.60
Top part oj uuejl end.
Breadth at bulge
4 60
‘ 4.26
Breadths, each a yard
382
higher than the other
2.18
1.64
5 )
16 50
Mean breadth
3 3
Height
4.0
9.70
half for a meanheight
4 -8s■>
43 «S
489
Area of bottom part of east end 9.11s
Mean breadth of top part 3.7height 4.;
TiJ
148
Area of top part of cast endArea of bottom part of east endArea of the east end
8.S
half for a meanheight
1 6.6s
9 *’ S
* 5 - 8 «S
4 31.6
Is8
43
Area of bottom part of west end 6.88Mean breadth of top part z-zheight 4
Area of top part of -
west end 13.x
Area of the west endArea of the cast end
Mean area
Length
Solidity
20
458.16
ao 0815.86s
10040
11048
16064
4016
519 36910 ( 11.78
4
4 ») "9
84
447 ) 3I3<S3'»S
10.08
ajjjtfj
3)ar7aS
11.908
mean.
4548) 4079136384
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